summing two 3d matrices to check convergence

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Thales
Thales am 5 Sep. 2017
Bearbeitet: Matt J am 5 Sep. 2017
Given two 3d matrices, obtained in a iterative process as the solution to a PDE, I want to check convergence. To do so, I check:
abs( sum( A(:) - Aold(:) ) ) < eps
Is this the best way to do it? I mean, if I declare
A = rand(100,200,50);
B = rand(100,200,50);
And if I check
check1 = abs( sum( A(:)-B(:) ) );
check2 = abs( sum(sum(sum( A-B ) ) ) );
check3 = abs( sum(A(:)) - sum(B(:)) );
check4 = abs( sum(sum(sum(A))) - sum(sum(sum(B))) );
They should give the same answer. However,
>> check1-check2
ans =
2.3306e-12
>> check1-check3
ans =
3.8846e-09
>> check1-check4
ans =
-2.4812e-10
>> check2-check3
ans =
3.8823e-09
>> check2-check4
ans =
-2.5045e-10
>> check3-check4
ans =
-4.1327e-09
So it clearly is not exactly the same thing. What is the difference between the methods and what is the difference between sum(A(:)) and sum(sum(sum(A))) ? If I want to check convergence on a iterative process, what is the best way to do it?
  1 Kommentar
Matt J
Matt J am 5 Sep. 2017
Bearbeitet: Matt J am 5 Sep. 2017
I think you really meant
sum(abs(A(:)-Aold(:)))<eps
This is the same as my Answer below, with p=1.

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Matt J
Matt J am 5 Sep. 2017
Bearbeitet: Matt J am 5 Sep. 2017
norm(A(:)-Aold(:),p)<eps
where you choose p corresponding to your favorite p-norm

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