Hello,
I write some code like this:
vx = 30:10:300;
vy = 2:0.04:3;
[xx,yy] = meshgrid(vx,vy);
zz = get_critical_value(yy,xx,0.05);
surf(xx,yy,zz)
Unfortunately, Matlab returns some feedback messages below:
======================================================
FZERO cannot continue because user-supplied function_handle ==>
@(czero)integral(@(y)fun(y,czero),0,3*Cp*sqrt(n))-alpha failed with the error below.
Inner matrix dimensions must agree.
Error in get_critical_value (line 15)
czero_sol = fzero(@(czero) integral(@(y)fun(y,czero),0,3*Cp*sqrt(n))-alpha,czero_guess);
======================================================
What's wrong with my program? How can I solve this situation to get the right plot? Thanks!
*The code of get_critical_value:
function czero_sol = get_critical_value(C,n,alpha)
if n<100
Cp = C+0.33;
else
Cp = C+0.12;
end
fun = @(y,czero)chi2cdf((n-1)*(3*Cp*sqrt(n)-y).^2/(9*n*czero^2),n-1).*(normpdf(y+3*(Cp-C)*sqrt(n))+normpdf(y-3*(Cp-C)*sqrt(n)));
czero_guess = 1;
czero_sol = fzero(@(czero) integral(@(y)fun(y,czero),0,3*Cp*sqrt(n))-alpha,czero_guess);
end

 Akzeptierte Antwort

Robert
Robert am 23 Aug. 2017

0 Stimmen

Your function get_critical_value is not build to handle array inputs. It is always nice if you can vectorize your function to take advantage of MATLAB's fast array operations but in your case, integral and fzero will make this difficult.
Instead of vectorizing, you could perform the operation one-at-a-time using arrayfun
vx = 30:10:300;
vy = 2:0.04:3;
[xx, yy] = meshgrid(vx, vy);
zz = arrayfun(@(y, x) get_critical_value(y, x, 0.05), yy, xx);
surf(xx, yy, zz)

1 Kommentar

Louis Liu
Louis Liu am 23 Aug. 2017
Thanks! But I think I have to study arrayfun() first. It's my first time to know this function. Hope I could truly understand whole your answer...

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am 29 Aug. 2017

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