Inverse Z-Transform of z/(z-a) - Strange result
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Gennaro Arguzzi
am 26 Jul. 2017
Kommentiert: fadli yusuf
am 23 Dez. 2020
Hello everyone, I tried to get the inverse Z-transform of z/(z-a) with the following lines:
close all
clear all
syms a n z
iz=iztrans(z/(z-a),z,n)
the result is:
piecewise([a == 0, kroneckerDelta(n, 0)], [a ~= 0, a*(a^n/a - kroneckerDelta(n, 0)/a) + kroneckerDelta(n, 0)])
but I expect a^n. How can I get a^n?
Thank you for your time.
1 Kommentar
Karan Gill
am 26 Jul. 2017
To add to Star Strider's answer below, your result contains the piecewise function. See that doc page for more info.
Akzeptierte Antwort
Star Strider
am 26 Jul. 2017
Specify ‘a>0’, and simplify:
syms a n z
assume(a > 0)
iz=iztrans(z/(z-a),z,n);
iz = simplify(iz);
iz =
a^n
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Arthur Ngnepiepaye
am 6 Nov. 2020
Can someone help me out plotting this zero input response? It's confusing
1 Kommentar
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