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i'm trying to make loop in a loop so for each index of alpha(the main loop) will path thru the all loop on v_0(the secondary loop) and store the wanted data on new vector. can someone tell me what wrong with my code
v_0=[3:0.1:20];
for i=1:size(alpha)
for j=1:size(v_0)
t=(5/49)*(v_0(j)*sin(a(i))+sqrt(v(j)^2*(sin(a(i)))^2-98/5));
x=v_0(j)*cos(a(i))*t;
v=zeros(size(alpha));
if x>7.15 || x<6.85
v(i)=1;
else
v(i)=0;
end
end
end
Antworten (1)
Andrei Bobrov
am 15 Jun. 2017
Bearbeitet: Andrei Bobrov
am 15 Jun. 2017
v_0=(3:0.1:20);
m = numel(alpha);
n = numel(v_0);
v = zeros(m,n);
for ii=1:m
for jj=1:n
t=(5/49)*(v_0(jj)*sin(a(ii))+sqrt(v_0(jj)^2*(sin(a(ii)))^2-98/5));
x=v_0(jj)*cos(a(ii))*t;
if x>7.15 || x<6.85
v(ii,jj)=1;
end
end
end
without loop for..end
MATLAB R2016b and later
a = a(:);
v_0 = v_0(:)';
t = v_0.*sin(a);
x = 5/49*v_0.*cos(a).*(t+sqrt(t.^2-98/5));
v = x > 7.15 || x < 6.85;
MATLAB R2016a and earlier
a = a(:);
v_0 = v_0(:)';
t = sin(a)*v_0;
x = 5/49*bsxfun(@times,cos(a)*v_0,(t+sqrt(t.^2-98/5)));
v = x > 7.15 || x < 6.85;
2 Kommentare
avner yakov
am 16 Jun. 2017
Andrei Bobrov
am 16 Jun. 2017
Hello Avner! Please accept this answer if it helped solve your problem.
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