How to plot the number of iterations as a function of the approximation

Hello, My code provides me with an approximation of pi based on the number of iterations required to escape the Mandelbrot set. I would like to plot the number of iterations (n) as a function of the Approximation, but I can't seem to get a decent graph. I have tried just plotting n,Approximations, as well as a loglog plot (since the iterations get rather large) and I tried changing the marker size encase it was too small. I also tried to create a new loop to save the value from each iteration in a zeros matrix and plot that, but didn't really get anywhere with it. Any thoughts or ideas would be most appreciated. Here is the code:

% Fifth Version

close all;clear all; clc

%Prepared by Lauren Stearns

prompt = 'Input a small, real, positive value for epsilon.  Input:';

epsilon = str2double(input(prompt,'s')); 

c = 1/4 + epsilon ;  
% Where epsilon is a very small, real, positive, number. such as 1e-10

z = 0;

n = 0;

while z < 2

z = z.^2 + c;

n = n+1 ;

end

Approximation = n*sqrt(epsilon);

display(Approximation)

format long

Pi = pi

Comparison = abs(((pi-Approximation)/pi))*100;  %%Percent error comparison

display(Comparison)

loglog(n,Approximation,'k-', 'markersize', 12)

Answer 1

[KSSV]

I literally, have no idea on what you are doing..but this can be done to plot number of iterations and approximation. You have to rethink on what you are doing:

close all;clear all; clc
%Prepared by Lauren Stearns
prompt = 'Input a small, real, positive value for epsilon.  Input:';
epsilon = str2double(input(prompt,'s'));
c = 1/4 + epsilon ;
% Where epsilon is a very small, real, positive, number. such as 1e-10
z = 0;
n = 0;
while z < 2
    z = z.^2 + c;
    n = n+1 ;
end
Approximation = [1:n]*sqrt(epsilon);
% display(Approximation)
format long

Comparison = abs(((pi-Approximation)/pi))*100;  %%Percent error comparison
% display(Comparison)
loglog(1:n,Approximation,'k-', 'markersize', 12)

[Lauren Stearns]

Thank you, that was all I needed :D