I wrote the code to plot two dimension graph but it is not showing the correct graph.So can you check and tell me where the mistake is in the code.
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
ploting two dimensional graph for u(x,t)=x*exp(-t)+exp(-x)
x=linspace(0,1,6);
y=linspace(0,1,6);
[X Y]=meshgrid(x,y);
z=x*exp(-y)+exp(-x);
mesh(x,y,z);
0 Kommentare
Antworten (2)
Star Strider
am 4 Jun. 2017
I created an anonymous function for ‘z’, that illustrates what you need to do to plot your function.
This works:
x=linspace(0,1,6);
y=linspace(0,1,6);
[X Y]=meshgrid(x,y);
z = @(x,y) x.*exp(-y)+exp(-x);
mesh(x,y,z(X,Y))
You need to use the meshgrid-created ‘X’ and ‘Y’ matrices to calculate ‘z’. You also need to use element-wise multiplication. See the documentation on Array vs. Matrix Operations for element-wise operations, and on Anonymous Functions for them.
You may also need to use the ‘X’ and ‘Y’ matrices in your mesh call. In recent MATLAB releases you can use the vectors. The alternative is:
mesh(X,Y,z(X,Y))
2 Kommentare
Star Strider
am 4 Jun. 2017
You need to use element-wise operations, as I mentioned in my original Answer.
Try this:
Z=X./(1+Y);
Note the ‘./’ denoting element-wise division, instead of ‘/’ denoting matrix right-division.
Walter Roberson
am 4 Jun. 2017
x = linspace(0, 1, 6);
y = linspace(0, 1, 6);
[X, Y] = meshgrid(x, y);
Z = X .* exp(-Y) + exp(-X);
mesh(X, Y, Z);
3 Kommentare
JEYGANESH JAYA KUMARAN
am 20 Jun. 2020
Hi, by using the above code, how to find value at a specific point in the mesh?
Siehe auch
Kategorien
Mehr zu Directed Graphs finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!