I have a table LC that has a column of dates called "date". The date format is however 19850331. I want to extract the year and the month of this date. How can I do so?

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Andrei Bobrov
Andrei Bobrov am 1 Jun. 2017
Bearbeitet: Andrei Bobrov am 1 Jun. 2017

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LC.date = datetime(sprintfc('%d',LC.date),'InputFormat','yyyyMMdd');
LC.month_year = [month(LC.date),year(LC.date)]

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Peter Perkins
Peter Perkins am 2 Jun. 2017

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Andrei provided the right answer if those data are text, e.g. '19850331' or "19850331". If they are numeric, use
datetime(LC.Date,'ConvertFrom','yyyymmdd')

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