Compare matrices with datenum

1 Ansicht (letzte 30 Tage)
David du Preez
David du Preez am 19 Mai 2017
Bearbeitet: Andrei Bobrov am 19 Mai 2017
Hi. I have 2 matrices. The first matrix A, (12x1) contains the monthly average values over 10 years. Row 1 is January, row 2 is February and so on. The second matrix B, is 8760x15. In column one there are hourly datenum values for an entire year and in column 15 there daily values. One value has been assigned for an entire day in column 15.
I want to remove an entire day if its value in column 15 is less than the corresponding monthly value in matrix A.
  2 Kommentare
Andrei Bobrov
Andrei Bobrov am 19 Mai 2017
Please attach B - matrix here.
David du Preez
David du Preez am 19 Mai 2017
Here is the correct B. It is just a sample of the matrix. Only has the 2 columns that relate to this question

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Andrei Bobrov
Andrei Bobrov am 19 Mai 2017
Bearbeitet: Andrei Bobrov am 19 Mai 2017
out = B(A(month(B(:,1))) <= B(:,end),:);

Kategorien

Mehr zu Dates and Time finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by