how to exit a for loop if a condition is true?!

hello! I would like to exit a for lopp is a condition is true but my code doesn't seem to work, could you help me to figure out where is the problem?! Thank you best regards!

    a= [ 1 2 3 5 8 6 8  8 2 8 2 8 2 8 2 1 nan 45 56 89];
    for i= 1:length(a)
    indx1 = find(isnan(a));
    if ~isempty (indx1)
       L = i ;
       return
    end
    end

[KSSV]

But what's the purpose of the code?

[Ano]

I need to get the index where the first nan is encountered and stop the loop as the main code should look for a critical point where the behavior starts to change

Answer 1

[KSSV]

a= [ 1 2 3 5 8 6 8  8 2 8 2 8 2 8 2 1 nan 45 56 89];
    for i= 1:length(a)
    indx1 = find(isnan(a));
    if ~isempty (indx1)
       L = i ;
       break
    end
    end

[Ano]

I have tried to use break but my L is always = 1, do you have any other suggestions ??!

[KSSV]

YOu can simply use

find(isnan(a))

Answer 2

[Walter Roberson]

L = find(isnan(a), 1, 'first');

with no loop.

You are testing the same vector of values each time, all of a, so your result would always be either 1 or not found.