Solving simultaneous equations numerically

4 Ansichten (letzte 30 Tage)
diana betancur
diana betancur am 10 Mai 2017
Bearbeitet: Walter Roberson am 11 Mai 2017
I am unable to get the value of R2 and C, any advice ... thank you
clear all
close all
syms s I1 I2 R2 C
a=8000
a1=4.08E7
l=1;
R=1E6;
e1=(s+R)*I1-R*I2==1;
i1=solve(e1,I1);
e2=-R*i1+(R2+R+1/(C*s))*I2==0;
i2=solve(e2,I2);
v0=(1/(C*s))*i2;
S=solve((1/(R*C+R*R2*C))==a,R/(R*C+R*R2*C)==a1)
  5 Kommentare
diana betancur
diana betancur am 11 Mai 2017
yes but I wanted to solve first for C and then plug it into the second equation to get a value for R2
Star Strider
Star Strider am 11 Mai 2017
That won’t work.
Eq1 = (1/(R*C+R*R2*C))==a;
Eq2 = R/(R*C+R*R2*C)==a1;
Eq1 = simplify(Eq1)
Eq2 = simplify(Eq2)
Cs = solve(Eq1, C)
Eq2s = subs(Eq2,C,Cs)
Eq2s = Eq2s * (8000000000*R2 + 8000000000)
R2s = solve(Eq2s,R2)
Eq1 =
8000000000*C*(R2 + 1) == 1
Eq2 =
40800000*C*(R2 + 1) == 1
Cs =
1/(8000000000*R2 + 8000000000)
Eq2s =
(40800000*(R2 + 1))/(8000000000*R2 + 8000000000) == 1
Eq2s =
40800000*R2 + 40800000 == 8000000000*R2 + 8000000000
R2s =
-1

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Symbolic Math Toolbox finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by