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How can I replace NaN elements with the nearest value in the same column?

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I am trying to replace NaN's in a vector field with the nearest value.
% I have:
M=
NaN 12
18 14
NaN NaN
NaN NaN
NaN 16
12 NaN
12 NaN
NaN 12
16 NaN
%I desire:
M=
18 12
18 14
12 16
12 16
12 16
12 12
12 12
16 12
16 12
Any information will be helpful. Thank you
  2 Kommentare
AstroGuy1984
AstroGuy1984 am 25 Apr. 2017
Bearbeitet: AstroGuy1984 am 25 Apr. 2017
What do you mean by "nearest"? Do you mean "next good value"? Because that's what you appear to desire. For example the second NaN in column 1 is closer to 18 than 12.
sal135
sal135 am 26 Apr. 2017
I would like to have the first value of NaN to have the value of the next good value. However if the last value in the column is a NaN I would like for it to have the value of the previous good value

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Andrei Bobrov
Andrei Bobrov am 25 Apr. 2017
Bearbeitet: Andrei Bobrov am 26 Apr. 2017
FIXED 2
m = flipud(M)
t = ~isnan(m);
ii = cumsum(t);
ii(ii == 0) = 1;
ii = bsxfun(@plus,[0,ii(end,1:end-1)],ii);
m1 = m(t);
out = flipud(m1(ii))
  6 Kommentare
Andrei Bobrov
Andrei Bobrov am 26 Apr. 2017
>> m = flipud(M);
t = ~isnan(m);
ii = cumsum(t);
ii(ii == 0) = 1;
ii = bsxfun(@plus,[0,ii(end,1:end-1)],ii);
m1 = m(t);
out = flipud(m1(ii))
out =
18 12
18 14
12 16
12 16
12 16
12 12
12 12
16 12
16 12
>>
sal135
sal135 am 26 Apr. 2017
Bearbeitet: sal135 am 27 Apr. 2017
Thank you for your help! This worked out great.

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dpb
dpb am 25 Apr. 2017

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