Count the frequent numbers in the matrix based on the sequence in the matrix ?

1 Ansicht (letzte 30 Tage)
I like to count the frequent numbers in the matrix based on the sequence in the matrix /// EX: Y = [ 5 4 4 2 ; 6 3 3 1 ;2 4 2 2; 5 5 6 1] The answer suppose to be like: 5 3, 4 3, 2 4 , 6 2, 3 2, 1 2 /// That mean the 5 repeated 2 times, the 4 repeated three times and so on .. /// The an important point is the number based on the sequence in the matrix which 5,4,2,6,3,1 /// not Descending or Ascending /// thanks

Akzeptierte Antwort

the cyclist
the cyclist am 22 Mär. 2017
Here's one way:
Y = [ 5 4 4 2 ; 6 3 3 1 ;2 4 2 2; 5 5 6 1];
YT = Y';
[uniqueY, ~, j] = unique(YT(:),'stable');
ycounts = histcounts(j,[unique(j); Inf]);
output = [uniqueY,ycounts']
  5 Kommentare
fathi
fathi am 15 Apr. 2017
Thank you, my friend, for your reply.It works. that is what I want exactly.
fathi
fathi am 30 Apr. 2017
good morning .. if I have 40 figures from the up ( last answer one ) from different 40 matrixes with 4*4 dim //// how can I represent them by one figure? I mean one generalized graph?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by