how to plot a surface in MATLAB?

1 Ansicht (letzte 30 Tage)
safi58
safi58 am 3 Feb. 2017
Kommentiert: Walter Roberson am 3 Feb. 2017
lamda=0.218;
rl=2.2;
N=20
[fi, fn] = meshgrid(linspace(10,180,N),linspace(1,2,N));
gamma=pi./fn;
x=1-cosd(fi);
a=1-cosd(fi);
b=(gamma/rl)*(1-0.5*(1-cosd(fi)));
c=(0.25*lamda*(fi.*pi/180).^2)*(1-cosd(fi));
d=0.5*lamda*(fi.*pi/180).^2;
e=0.5*(fi.*pi/180).^2*lamda;
f=0.5*(fi.*pi/180)*lamda*sind(fi);
g=(0.5*(fi.*pi/180).^2*lamda)*(1-cosd(fi));
h=(0.25*(fi.*pi/180)*lamda*gamma)*(1-cosd(fi));
den=a+b-c+d-e+f-h+g;
Gdc=x./den
surf(fi, fn, Gdc, 'edgecolor', 'b')
I have to plot a surface by these equations but it is not giving me what i expected. Can anyone help me?
  2 Kommentare
John BG
John BG am 3 Feb. 2017
is this what you expect?
.
John BG
safi58
safi58 am 3 Feb. 2017
Hi, Jon. No, I would not expect it. I would expect like this

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 3 Feb. 2017
You did not give us any ideas what you were expecting so it is difficult to debug.
Possibly in c, g, h, you want .* (1-cosd(fi)) instead of * (1-cosd(fi))
By the way, for efficiency you should calculate (1-cosd(fi)) only once and use the result multiple times.
  4 Kommentare
safi58
safi58 am 3 Feb. 2017
Bearbeitet: Walter Roberson am 3 Feb. 2017
Gdc=(1-cos(fi))/((1-cosd(fi))+((gamma/rl)*(1-0.5.*(1-cosd(fi))))-((0.25*lamda*(fi.*pi/180).^2).*(1-cosd(fi)))+(0.5*lamda*(fi.*pi/180).^2)-(0.5*(fi.*pi/180).^2*lamda)+(0.5*(fi.*pi/180)*lamda.*sind(fi))-((0.25*(fi.*pi/180)*lamda*gamma).*(1-cosd(fi)))+(0.5*(fi.*pi/180).^2*lamda).*(1-cosd(fi)))
where fi= 0 to 180 degree, fn=0.1 to 5, lamda= 0.218, rl=2.2, gamma=pi/fn
Walter Roberson
Walter Roberson am 3 Feb. 2017
I was hoping for mathematical equations, to reduce the ambiguity of .* compared to * as you coded some multiplications with * (algebraic matrix multiplication).
What you just posted contains in part
+(0.5*lamda*(fi.*pi/180).^2)-(0.5*(fi.*pi/180).^2*lamda)
As lamda is a scalar rather than a matrix, the lamda can be moved in front in both subexpressions,
+(0.5*lamda*(fi.*pi/180).^2)-(0.5*lamda*(fi.*pi/180).^2)
and you can see that the two sub-expressions are the same but of opposite signs and so will cancel out to 0. In your original question these were d and e
In the below code I have left them in as expressions d and e even though they mathematically cancel out, so as to make it easier for you to find the place that will have to be changed.
N = 50;
fi = linspace(0, 180, N) * pi/180;
fn = linspace(0.1, 5, N);
[FI, FN] = ndgrid(fi, fn);
lamda= 0.218;
rl = 2.2;
GAMMA = pi ./ FN;
cosFI = cos(FI);
M1cosFI = 1 - cosFI;
FIlamda = lamda .* FI;
FI2lamda = FIlamda .* FI;
d = (0.5*FI2lamda);
e = (0.5*FI2lamda);
Gdc = M1cosFI ./ (M1cosFI + ((GAMMA/rl) .* (1-0.5.*M1cosFI)) - ((0.25*FI2lamda).*M1cosFI) + d - e + (0.5*FIlamda.*sin(FI)) - ((0.25*FIlamda.*GAMMA).*M1cosFI) + (0.5*FI2lamda).*M1cosFI);
surf(FI, FN, Gdc)
This implements the equations fairly efficiently, but the outcome is not like you had hoped, which is partly due to the problem with d and e. But only partly -- over those ranges, these equations have a bunch of narrow peaks that would be difficult to miss if you happened to plot at the wrong resolution or with slightly the wrong locations.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by