2D Section of 3D coordinates

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fauer781
fauer781 on 14 Dec 2016
Commented: fauer781 on 15 Dec 2016
Hello, I have a 3D plot and the x y z coordinates of corresponding vertices as vectors n:1, m:1 and p:1. There is no function f(x,y,z). From theses vertices I want to get a 2D profile of an arbitrary sectionplane. It's possible that the points are not part of the plane. Is there a function for this problem?

Accepted Answer

Matt J
Matt J on 14 Dec 2016
Edited: Matt J on 14 Dec 2016
I think you can do it all just by using coordinate transformations. Transform your x,y,z coordinates so that the origin and the x,y axes lie in the plane of interest. Then throw away all (x,y,z) data whose distance from the plane (as measured by the new z coordinates) are too large in magnitude. Then, make a 2D plot of the (x,y) in the data that remain.
  1 Comment
fauer781
fauer781 on 15 Dec 2016
Thank you, I will try that. It's a good idea.

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More Answers (1)

Kelly Kearney
Kelly Kearney on 14 Dec 2016
The slice function may be of use here.
  1 Comment
fauer781
fauer781 on 14 Dec 2016
Hello, thank you for answering. I checked the slice function, but I don't have the m-by-n-by-p volume array. Only the x,y,z positions are available. How can I get the volume array with this information? There is no function depending on x,y,z.

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