Help with Newton's method function?

9 Ansichten (letzte 30 Tage)
Lauren Hux
Lauren Hux am 20 Nov. 2016
Kommentiert: Walter Roberson am 20 Nov. 2016
This is the function I've been making to run Newton's method, but I can't get it to work. Any help with what I might be missing? Thanks!
function xn = newtonmethod(f,fd,x0,tol)
xn=x0;
err=abs(f(xn)-0);
i=0;
while err>tol
i=i+1;
xnew=xn-(f(xn)/fd(xn));
err=abs(f(xnew)-0);
end

Antworten (1)

Walter Roberson
Walter Roberson am 20 Nov. 2016
I suspect your
err=abs(f(xnew)-0);
should be
err=abs(f(xnew)-f(xn));
unless you know that your f() has a "right" value of 0.
  2 Kommentare
Lauren Hux
Lauren Hux am 20 Nov. 2016
It does. Do you see anything else wrong with the code?
Walter Roberson
Walter Roberson am 20 Nov. 2016
You do not update xn = xnew

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by