Issue with multiple loops
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Hi,
Having an issue with the code below. Basically I want the loop to loop through each of the "en" (or entry) values. When outputting, the entry values are correct, but it is not used in calculations - what am I missing here?
en=2:0.5:6; % entry threshold (standard deviations)
ex=1; % exit threshold (standard deviations)
for entry=en
for i=1:(4630-lookback-1) % In sample
%for i=4631:(size(CO1)-lookback-1) % Out of sample
if zCO1(i)<-entry
while zCO1(i)<ex
pos(i)=1;
i=i+1;
end
elseif zCO1(i)>entry
while zCO1(i)>-ex
pos(i)=-1;
i=i+1;
end
end
end
for i=1:(4630-lookback-1) % In sample
%for i=4631:(size(CO1)-lookback-1) % Out of sample
if pos(i) == 1
ret(i)=retCO1(i+1);
elseif pos(i) == -1
ret(i)=-retCO1(i+1);
else
ret(i)=0;
end
end
fprintf('\nEntry'); disp(entry);
fprintf('Cumulative return');disp(sum(ret));
fprintf('Sharperatio');disp((sqrt(252)*mean(ret))/std(ret));
fprintf('Calmar');disp(sum(ret)/(std(ret)*252));
fprintf('**********************');
end
and the output is like:
Entry 2
Cumulative return 0.4896
Sharperatio 0.1242
Calmar 0.1428
**********************
Entry 2.5000
Cumulative return 0.4896
Sharperatio 0.1242
Calmar 0.1428
**********************
Entry 3
Cumulative return 0.4896
Sharperatio 0.1242
Calmar 0.1428
**********************
Tnx, Egert
0 Kommentare
Antworten (2)
Oleg Komarov
am 5 Mär. 2012
You're changing the i (used by the for loop) within the while loop. You can do it but it is usually not recommended.
I don't have data to test the implications but most likely that's the cause.
0 Kommentare
egert
am 5 Mär. 2012
2 Kommentare
Oleg Komarov
am 5 Mär. 2012
If you describe what your problem is and what is your data with a minimum working example it would be much easier. I also suspect that no loops are needed at all. It's a logical indexing problem.
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