I have a matrix
A = [1 2 3; 3 4 5; 1 2 3];
I want to identify the duplicate row i.e. 3rd row and replace the values in that row by 0.
Resultant A = [1 2 3; 3 4 5; 0 0 0];
Is there an efficient way to do this? Thanks in Advance.

 Akzeptierte Antwort

Massimo Zanetti
Massimo Zanetti am 6 Okt. 2016

8 Stimmen

You can identify the repeated rows by invoking unique function of Matlab, and then set to 0 non-unique rows as follows:
[C,ia,ib]=unique(A,'rows','stable');
i=true(size(A,1),1);
i(ia)=false;
A(i,:)=0;
Then A will be your output.

Weitere Antworten (1)

KSSV
KSSV am 6 Okt. 2016

3 Stimmen

A = [1 2 3; 3 4 5; 1 2 3];
[C,ia,ic] = unique(A,'rows') ;
iwant = zeros(size(A)) ;
iwant(ia,:) = C ;

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