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Syntax x = fmin('fun',x1,x2)

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work wolf
work wolf am 31 Aug. 2016
Kommentiert: Star Strider am 1 Sep. 2016
Syntax
x = fmin('fun',x1,x2)
x = fmin('fun',x1,x2,options)
x = fmin('fun',x1,x2,options,P1,P2, ...)
[x,options] = fmin(...)
are not working by matlab? the message from matlab as follows as:
>> f =@(x) x.^3-2*x-5;
>> x = fmin('f', 0, 2)
Undefined function 'fmin' for input arguments of type 'char'.
Did you mean:
>> x = min('f', 0, 2)
Error using min
MIN with two matrices to compare and a working dimension is not supported.
>> x = fminbnd('f', 0, 2)
Cannot find an exact (case-sensitive) match for 'f'

Akzeptierte Antwort

Star Strider
Star Strider am 31 Aug. 2016
You’re almost there.
This works:
f =@(x) x.^3-2*x-5;
x = fminbnd(f, 0, 2)
x =
816.4968e-003
  18 Kommentare
work wolf
work wolf am 1 Sep. 2016
Relly , thank you sooooo much
Star Strider
Star Strider am 1 Sep. 2016
As always, my pleasure!

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 31 Aug. 2016
"Note: The fmin function was replaced by fminbnd in Release 11 (MATLAB 5.3). In Release 12 (MATLAB 6.0), fmin displays a warning message and calls fminbnd."
If you are using MATLAB 5.3 or earlier, that is important information for us to know. If you are using something that old, you would use
x = fmin('f', 0, 2)
but you would also have to have created file f.m with content
function y = f(x)
y = x.^3-2*x-5;
  2 Kommentare
work wolf
work wolf am 31 Aug. 2016
x = fmins('fun',x0)
x = fmins('fun',x0,options)
x = fmins('fun',x0,options,[],P1,P2, ...)
[x,options] = fmins(...)
and
z = fzero('fun',x) z = fzero('fun',x,tol)
z = fzero('fun',x,tol,trace)
z = fzero('fun',x,tol,trace,P1,P2,...)
thankx, if the fmin function was replaced by fminbnd, what were replaced fmins and fzero?
Steven Lord
Steven Lord am 31 Aug. 2016
fmins -> fminsearch
fzero -> fzero

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