How to use variable in a function?
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Ayesa
am 24 Feb. 2012
Bearbeitet: Azzi Abdelmalek
am 25 Okt. 2013
Hello. I am trying to make a function which will take strings as input (where string contains 3 characters: 0, +, -) and any '+' or '-' character will be replaced by '0'.
Now i want to add a variable which determines how many '+' or '-' will be replaced by '0'. But i am not getting any idea how to add it in the function. I want to add this variable because input_strings and working_variable will be changing continously. Following is my code:
function replacement_result = replacement(input_strings, working_variable)
for i1 = 1 : size(input_strings,1)
a = 0;
for j1 = size(input_strings,2): -1 : 1
if input_strings(i1,j1) == '0';
a = a+1;
else break,
end
end
for k1 = (size(input_strings,2)-a): -1 : 1
if input_strings(i1, k1) ~= '0'
input_strings(i1, k1) = '0';
else break,
end
end
end
replacement_result = input_strings;
If input_strings = [0+0-00-0+, +0+0-0+0-, -0-00-0+0], then if working_variable = 1, so replacement_result = [0+0-00-00, +0+0-0+00, -0-00-000]
If input_strings = [0+0-00-0+, +0+0-0+0-, -0-00-0+0], then if working_variable = 3, so replacement_result = [0+0000000, +0+000000, -00000000]
How can i add 'working_variable' in this function? Can any one please give me any idea?
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Akzeptierte Antwort
Geoff
am 24 Feb. 2012
A lot of people may ignore this question because it's about programming rather than MatLab, specifically... But it would help you to know that MatLab has a lot of powerful functions and constructs that can do the work for you.
In your case, you can use cellfun to iterate over your cell of strings, find to search for the required number of +/- chars, and lambda functions to make the notation a little clearer.
function [replacement_result] = replacement(input_strings, working_variable)
replacement_result = cellfun( ...
@(x) replace_n(x,working_variable), ...
input_strings, 'UniformOutput', false );
end
function [str] = replace_n( str, n )
f = @(x) find( x=='-' | x=='+', n, 'last' );
str(f(str)) = '0';
end
Now you can do:
>> input_strings = {'0+0-00-0+', '+0+0-0+0-', '-0-00-0+0'};
>> replacement(input_strings,1)
ans =
'0+0-00-00' '+0+0-0+00' '-0-00-000'
>> replacement(input_strings,2)
ans =
'0+0-00000' '+0+0-0000' '-0-000000'
>> replacement(input_strings,10)
ans =
'000000000' '000000000' '000000000'
-g-
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