hi, i use the following code . the output is 15 values , i want stored this values automatically in array in order to Call these values again

for sw=1:15
  n=[10;20;30;40;50;60;70;80;90;100];phi=0.5;
  s=2;
  z0=0.4;
  index=0;
  o=10;
  for nn=1:o
    a=normrnd(0,s^2,n(nn),1);
    z=zeros(n(nn),1);
    z(1)=phi*z0+a(1);
    for i=2:n(nn)
      z(i)=phi*z(i-1)+a(i);
    end
    for i=2:n(nn)
      g(i)=z(i)*z(i-1);
    end
    k=sum(g,2);
    num= (n(nn)-2)*k;
    for i=3:n(nn)
      f(i)=z(i-1)*z(i-1);
    end
    p=sum(f,2);
    den=(n(nn)-1)*p;
    index=index+1;
    ma(index)=n(nn);
    phihat(index)=num/den;
  end
  for i=1:o
    da(i)=(phihat(i)-phi)^2;
  end
  MSEreal=num2str((sum (da)/(o)),'% .10f')
end

Answer 1

[Star Strider]

I would just do:

MSEreal(sw) =sum((da)/(o));

There’s absolutely no need to convert them to a string array, since you have to convert them back to numeric to use them later. If you want to round them to 10 digits to the right of the decimal, use the latest version of the round function, or this anonymous funciton to do the same thing:

roundn = @(x,n) round(x .* 10.^n)./10.^n;   % Round ‘x’ To ‘n’ Digits, Emulates Latest ‘round’ Function

[mohammed elmenshawy]

thank u very very much

[Star Strider]

My pleasure.