How to replace any value into vector or matrix to -inf

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Triveni
Triveni am 12 Jul. 2016
Kommentiert: Walter Roberson am 12 Jul. 2016
ab =
11.0000
11.5000
12.0000
12.1000
12.2000
12.3000
11.2000
9.0000
9.5000
11.3000
ab<10
ans =
Columns 1 through 9
0 0 0 0 0 0 0 1 1
Column 10
0
ab1
ab1 =
Columns 1 through 5
11.0000 11.5000 12.0000 12.1000 12.2000
11.1000 11.4000 12.0000 12.1000 12.2000
Columns 6 through 10
12.3000 11.2000 9.0000 9.5000 11.3000
12.3000 11.2000 9.0000 9.5000 11.3000
>> ab1<10
ans =
Columns 1 through 9
0 0 0 0 0 0 0 1 1
0 0 0 0 0 0 0 1 1
Column 10
0
0
i want to replace ab<10 to -inf, without loop, and other variables and matrix size remains same. It should be applicable to any type of matrix.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 12 Jul. 2016
ab(ab<10) = -inf;
  2 Kommentare
Triveni
Triveni am 12 Jul. 2016
Bearbeitet: Walter Roberson am 12 Jul. 2016
Sir, If i need to be make other matrix's index -inf then how can i do?.
f_data =
1.0000
13.5000
11.0000
12.1000
12.2000
13.3000
11.2000
13.0000
13.5000
8.3000
In both matrices any index<10, i have to make both corresponding matrix -inf.
Walter Roberson
Walter Roberson am 12 Jul. 2016
mask = ab<10 | f_data<10;
a(mask) = -inf;
f_data(mask) = -inf;

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