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how i can use x(t) & ... in my program

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behnam
behnam am 16 Feb. 2012
Bearbeitet: Matt J am 15 Okt. 2013
i use this code but matlab show me an eror how i can fix this eror
also i want plot (>) with angle fee how i can do that ?
clear all
t=0;
x(t)=input('Enter X(0) =');
y(t)=input('Enter Y(0) =');
fee(t)=input('Enter Fee(0) =');
for (x(t+1)~=10)&&(fee(t+1)~=90)
t=t+1;
plot(x(t),y(t),'>');
x(t+1)=x(t)+cos(fee(t)+teta(t))+sin(teta(t))*sin(fee(t));
y(t+1)=y(t)+sin(fee(t)+teta(t))-sin(teta(t))*cos(fee(t));
fee(t+1)=fee(t)-asin((2*sin(teta(t)))/4);
end

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 16 Feb. 2012
MATLAB does not permit the value 0 to be used as a vector index. Vector indexes must be integers 1 or greater.
Requesting '>' as the plot marker gets you a right-pointing triangle. If you want an open arrow instead, then you will need to draw in the markers yourself at each location.

Weitere Antworten (2)

behnam
behnam am 16 Feb. 2012
thank you but now i receive this message : ??? Attempted to access x(2); index out of bounds because numel(x)=1.
  1 Kommentar
Walter Roberson
Walter Roberson am 16 Feb. 2012
If, hypothetically, MATLAB allowed x(0) to be defined, then you would still have had this problem anyhow, because of your line
for (x(t+1)~=10)&&(fee(t+1)~=90)
which, besides being syntactically invalid for a "for" loop, would attempt to access x(1) at a time when only x(0) had been defined.
Your code is non-functional in such a manner that we cannot make a reasonable guess about what you were attempting to write.

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behnam
behnam am 16 Feb. 2012
i mean i edited my m-file code as below :
please if possible edit my m-file into correct
clear all
t=1;
x(t)=input('Enter X(0) =');
y(t)=input('Enter Y(0) =');
fee(t)=input('Enter Fee(0) =');
plot(x(t),y(t),'>');
i=1;
if (x(t)~=10)&&(fee(t)~=90)
x(t+1)=x(t)+cos(fee(t)+teta(t))+sin(teta(t))*sin(fee(t));
y(t+1)=y(t)+sin(fee(t)+teta(t))-sin(teta(t))*cos(fee(t));
fee(t+1)=fee(t)-asin((2*sin(teta(t)))/4);
plot(x(t+1),y(t+1),'>');
t=t+1;
end
  1 Kommentar
Walter Roberson
Walter Roberson am 16 Feb. 2012
Do you want a "while" loop instead of "if" ? If so then you would move the plot() to after the "while" and would
plot(x, y, '>')
However! See
http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
as otherwise your loop might never terminate.

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