Does NaN used in confusion matrix affects results?
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Ekta Sharma
am 15 Jun. 2016
Kommentiert: Chad Greene
am 17 Jun. 2016
I have used confusion matrix and for making two matrices of equal dimensions I had used NaN but is it wise to use that? for example: A= [2 3 7 ]; B= [3 4 NaN]; C= A+B; C= 5 7 NaN I am getting where result should have been [5 7 7] according to me.Can anyone help? Thanx in advance.
3 Kommentare
Akzeptierte Antwort
Chad Greene
am 16 Jun. 2016
Here's one way:
C = nansum([A; B])
C =
5 7 7
2 Kommentare
Chad Greene
am 17 Jun. 2016
Using NaN as a place filler is often the best way to do it. The reason 1+NaN=NaN is because Matlab doesn't what the answer is if you add a number to something that is not a number. But the nansum function and its sisters (nanmean, nanmedian, etc) are available to simply ignore NaNs the way you want.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!