how to delete rows from matrix
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m. muner
am 24 Mai 2016
Kommentiert: Anoire BEN JDIDIA
am 17 Okt. 2016
hello i have 53*3 matrix but include rows that three column of the row are zeros i want to delete the entire row i tried this but since every delete shift the location of the other rows i had problem with the for loop so what can i do to overcome this
[c u]=size(test_ary); %dimensions
for i=1:c
for b=1:u
if(test_ary(i,1)==(o)));
test_ary(i,:)=[];
end
end
end
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Akzeptierte Antwort
James Tursa
am 24 Mai 2016
Bearbeitet: James Tursa
am 24 Mai 2016
Replace your for-loop with this vectorized code:
x = all(test_ary==0,2); % Which rows are all 0's
test_ary(x,:) = []; % Delete those rows
Weitere Antworten (3)
Jos (10584)
am 26 Mai 2016
Using the statement "test_ary(i,:) = []" you will change the size of it, which will cause problems!
tf = all(test_ary==0,2) % true for rows with only 0's
test_ary(tf,:) = [] % remove those rows using logical indexing
Anoire BEN JDIDIA
am 14 Okt. 2016
I have a big matrix 599794x2 i want to delete rows which contains values which repeats for exemple if A=[1,1;2,1;3,1;4,1;5,2;6,2;7,2]; i want to have A=[1,1;5,2]
2 Kommentare
James Tursa
am 14 Okt. 2016
In the future open up a new Question for this rather than piggyback on an existing Question. But I will answer this here this time:
A = A(logical([1;diff(A(:,2))]),:);
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