# Whats wrong with my quadratic formula?

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Collin Kerr on 19 Apr 2016
Answered: Roger Stafford on 19 Apr 2016
V_o = input('Velocity at launch = ');
Theta = input('Elevation angle at launch = ');
a=9.81; %Its a given
b=V_o*sind(Theta) %It makes the coding a bit less confusing.
c=0; %Also a given
fprintf('The velocity for the launch is %d meters per second. \n', V_o)
fprintf('The elevation angle for the launch is %d degrees. \n', Theta)
Q1=(-b-sqrt(b^2-4*a*c))/2*a;
disp(Q1)
For some reason the code is not lining up with a calculators numbers. I was wondering if someone could explain what specifically is wrong with the quadratic formula and how could I be able to fix it?
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### Accepted Answer

James Tursa on 19 Apr 2016
Edited: James Tursa on 19 Apr 2016
You need to enclose the denominator in parentheses:
Q1=(-b-sqrt(b^2-4*a*c))/(2*a);
The way you have it coded, since / and * have the same precedence the operations are performed left to right and MATLAB sees your current coded expression as:
Q1=((-b-sqrt(b^2-4*a*c))/2) * a;
Which is not what you wanted.
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### More Answers (1)

Roger Stafford on 19 Apr 2016
Apparently you are trying to see how many seconds the object in question would take to return to earth. The velocity equation is:
v = -a*t+b
If you integrate with respect to t, you get
x = int(v,t) = -a*t^2/2+b*t
The solution is either t = 0 (the beginning) or t = b/(2*a) (at the end.) Your mistake was twofold. You had a positive value for a, and you didn't include the 1/2.
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