Subscripted dimension mismatch error dec2hex

Hello
I searched regarding this error but still could not resolve it. I am using the following code:
function[hexoutput] = hexaoutput(colordata)
[row col] = size(colordata);
hexoutput=zeros(row,col);
for i=1:row
for j=1:col
hexoutput(i,j) = dec2hex(colordata(i,j),6);
end
end
end
I am getting the subscripted dim mismatch error. But this is how we loop through a matrix. I am confused. Any help would be great. Thanks.

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 13 Apr. 2016

1 Stimme

dec2hex(SOMETHING,6) is going to return 6 (or more) characters. You then try to store those 6 characters into a single numeric array location. Remember, hex is represented as character, but zeros() is numeric, so you are using the wrong datatype for your output array and you are not allowing for the fact that each output needs multiple characters.

3 Kommentare

Panda
Panda am 13 Apr. 2016
Bearbeitet: Panda am 13 Apr. 2016
aha....I get it...what is the way around this then sir? If I want a matrix to be converted to hex values then what changes should I do in my code? The matrix is 122X400...I know its quite large. Could you help here then...? Thanks!
EDIT: ok, I managed to do it. I declared hexoutput as a cell array and then did the same thing. It worked. My another question is - Can't we represent hex in 0X** format?
Walter Roberson
Walter Roberson am 13 Apr. 2016
Consider using sprintf('0x%06x', colordata(i,j))
Panda
Panda am 13 Apr. 2016
Bearbeitet: Panda am 13 Apr. 2016
Brother you are simply great!! :) :D Thank you so much!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Roger Stafford
Roger Stafford am 13 Apr. 2016

1 Stimme

The dec2hex(colordata(i,j),6) quantity is a string of at least six hex characters, and yet your are attempting to place it in a single element of hexoutput. It won't fit. You'll have to make hexoutput bigger! Maybe you'd like to make it three-dimensional.

1 Kommentar

Panda
Panda am 13 Apr. 2016
Same ans as above sir...understood my mistake. Thanks

Melden Sie sich an, um zu kommentieren.

Kategorien

Gefragt:

am 13 Apr. 2016

Bearbeitet:

am 13 Apr. 2016

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by