Constant number is changing value, why?

4 Ansichten (letzte 30 Tage)
Krish Desai
Krish Desai am 25 Mär. 2016
Bearbeitet: dpb am 25 Mär. 2016
So I have a 1 that should print out, but instead only on the first line does 1 print out, for the rest the number keeps changing. Why?
dt=5*10e-5;
timenumber=0;
for t=0:dt:2*dt %99 for 100 graphs
figure;
atom=1;
for ind=1:1920
U=(3*ind+linspace(1,3,3)-3);
Phi= PHI_disp_RBME_ModePlot_N(U);
r=xlocs_full(ind);
omega=(f_disp_RBME(iMode,kPtMode)*2*pi);
k=kappa_space(kPtMode);
spatialphase=k*r;
timephase=omega*t;
displ=Phi*exp(i*((spatialphase)-(timephase)));
xOvito(ind)=xOvito(ind)+magFact*displ(1);
yOvito(ind)=yOvito(ind)+magFact*displ(2);
zOvito(ind)=zOvito(ind)+magFact*displ(3);
header0= 'Timestep:';
header1= 'id';
header2= 'type';
header3='x';
header4='y';
header5='z';
headernum='Number of atoms:';
timenumber=(timenumber+1);
if ind==1
fileName=['dump',num2str(t*2000)];
end;
fid=fopen(fileName,'w');
fprintf(fid, [ header0 '\n']);
fprintf(fid, '%d \n', (timenumber/1920)-1');
fprintf(fid, [headernum '\n']);
fprintf(fid, '%d \n', 1920);
fprintf(fid, [ header1 ' ' header2 ' ' header3 ' ' header4 ' ' header5 '\n']);
fprintf(fid, '%f %f %f %f \n', [1 xOvito yOvito zOvito]');-------------->The one keeps changing
fclose(fid);
end

Antworten (1)

dpb
dpb am 25 Mär. 2016
Bearbeitet: dpb am 25 Mär. 2016
...
for ind=1:1920
...
xOvito(ind)=xOvito(ind)+magFact*displ(1);
yOvito(ind)=yOvito(ind)+magFact*displ(2);
zOvito(ind)=zOvito(ind)+magFact*displ(3);
... header0= 'Timestep:';
fprintf(fid, '%f %f %f %f \n', [1 xOvito yOvito zOvito]'); % The one keeps changing
...
Because as the above reduced code snippet shows, you're building arrays from 1:1920 for each of the three variables in the loop and the fprintf argument list uses the variable names without subscripting. So, each pass through the loop you'll get first one set of values, then two for each, then three, etc., ... Since the format is for four elements per output record, they'll wrap and the position of each relatively to each other will change each pass.
You undoubtedly intended to write
fprintf(fid, '%f %f %f %f \n', [1 xOvito(ind) yOvito(ind) zOvito(ind)]');
In summary, the '1' didn't change its value, it simply gets placed in a different location owing to the number of values being printed each pass through the loop.
ADDENDUM
While not related to the issue, you'll save quite a lot if you preallocate the three arrays before beginning the loop over ind --
...
xOvito=zeros(1920,1); % preallocate
yOvito=zeros(1920,1); % preallocate
zOvito=zeros(1920,1); % preallocate
for ind=1:1920
...
xOvito(ind)=xOvito(ind)+magFact*displ(1);
yOvito(ind)=yOvito(ind)+magFact*displ(2);
zOvito(ind)=zOvito(ind)+magFact*displ(3);
...

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