How to count the number of zero subcells in a cell?

I have a cell array 12*32. each element of my cell contains 32 data. for example C{11,32}='0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ' . I want to count how many of zero array like above is there in my cell. could any one help me? thanks

[Walter Roberson]

Insufficient information about what else might be in the string, and whether you also need to find 0's expressed as 0. or .0 or 0.0 or 0.E+0 (and so on)

[Fateme Jalali]

t1 and t2 are my database.In this code I want to count howmany '0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0' happens in diffrcell

[Star Strider]

See: How to detect number of zero string in a cell

Answer 1

[Thorsten]

If you have a cell array of matrices:

C{1,1} = ones(1,32);
C{1,2} = 2*ones(1,32);
C{2,1} = zeros(1,32);
C{2,2} = zeros(1,32);

N = nnz(cellfun(@(x) nnz(x)==0, C));

If you have a cell array of cells, an additional cell2mat is needed:

 C = {{rand(5,1)}, {rand(7,1)}, {zeros(6,1)}, {rand(7,1)}, {0 1 2 3}, {-1 1}};
 N = nnz(cellfun(@(x) nnz(cell2mat(x))==0, C));

Answer 2

[Walter Roberson]

Most of the code can be replaced.

tt2u = unique(tt2{1}, 'rows');
tt3u = unique(tt3{1}, 'rows');
number_of_similar_chunks = sum( ismember(tt2u, tt3u) );

However you should clarify how you want the counting to occur if there are duplicate entries in one of the array that match the other array.