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how to divide a color image into blocks?

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yashi gautam
yashi gautam am 16 Nov. 2015
Kommentiert: Walter Roberson am 25 Aug. 2017
sir, my project is watermarking into a colored image(divided into 128x128 dimension 4 blocks) using dwt and svd technique.
I have written the following code for the full color image dwt and svd.
clc
close all
%original image
org_img=imread('lena.jpg');
figure;
imshow(org_img);
title('Original color image');
[h_LL,h_LH,h_HL,h_HH]=dwt2(org_img,'haar');
img=h_LL;
red1=img(:,:,1);
green1=img(:,:,2);
blue1=img(:,:,3);
[U_imgr1,S_imgr1,V_imgr1]= svd(red1);
[U_imgg1,S_imgg1,V_imgg1]= svd(green1);
[U_imgb1,S_imgb1,V_imgb1]= svd(blue1);
%watermark imagee
org_img=imread('fruits.jpg');
figure;
imshow(org_img);
title('Watermark image');
[w_LL,w_LH,w_HL,w_HH]=dwt2(org_img,'haar');
img_wat=w_LL;
red2=img_wat(:,:,1);
green2=img_wat(:,:,2);
blue2=img_wat(:,:,3);
[U_imgr2,S_imgr2,V_imgr2]= svd(red2);
[U_imgg2,S_imgg2,V_imgg2]= svd(green2);
[U_imgb2,S_imgb2,V_imgb2]= svd(blue2);
% watermarking by SVD
S_wimgr=S_imgr1+(0.10*S_imgr2);
S_wimgg=S_imgg1+(0.10*S_imgg2);
S_wimgb=S_imgb1+(0.10*S_imgb2);
wimgr = U_imgr1*S_wimgr*V_imgr1';
wimgg = U_imgg1*S_wimgg*V_imgg1';
wimgb = U_imgb1*S_wimgb*V_imgb1';
wimg=cat(3,wimgr,wimgg,wimgb);
newimage_LL=wimg;
%output
rgb2=idwt2(newimage_LL,h_LH,h_HL,h_HH,'haar');
imwrite(uint8(rgb2),'Watermarked.jpg');
figure;imshow(uint8(rgb2));title('Watermarked Image');
kindly tell me how to divide this host image 'lena.jpg' into 4 blocks of size 128x128 using either a looping technique or mat2cell. also dierct me if i can use functions to access differnt blocks of the image.
regards
Yashi
  2 Kommentare
TUSHAR MURATKAR
TUSHAR MURATKAR am 25 Aug. 2017
i have one question. after running this code i got cellarray of size 2x2. This i understood . but each cell is of size 192x56 . why it is like this why not 128x128 ? any help will be appreciated.
Walter Roberson
Walter Roberson am 25 Aug. 2017
The above code does not create cell arrays. The code I posted does.
What does size(org_img) show for you?

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Walter Roberson
Walter Roberson am 16 Nov. 2015
img4x4 = mat2cell( org_img, size(orig_img,1)/2 * ones(1,2), size(orig_img,2)/2 * ones(1,2), size(orig_img,3) );
  3 Kommentare
Walter Roberson
Walter Roberson am 16 Nov. 2015
img4x4{1,1} %upper left
img4x4{1,2} %upper right
img4x4{2,1} %lower left
img4x4{2,2} %lower right
I should have called it img2x2 intead of img4x4 though ;-)
yashi gautam
yashi gautam am 16 Nov. 2015
Thank you sir.. True.. img2x2 was more logical :) thanks a ton for the help. regards yashi

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