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Thorsten
Thorsten am 5 Nov. 2015
Bearbeitet: Thorsten am 5 Nov. 2015

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You can pull the w_i and sigma_i outside of the sum_j, because the don't depend on j. And you can compute the sum_j nicely as a matrix multiplication of row vector w and column vector sigma.
w = rand(1,10); % sample values for w and s
s = rand(10, 1);
N = numel(w);
y = 0;
for i=1:N-1
y = y + s(i)*w(i)* w(i+1:end)*s(i+1:end);
end
y = 2*y;

2 Kommentare

fede
fede am 5 Nov. 2015
give me Error using * Inner matrix dimensions must agree.
Torsten
Torsten am 5 Nov. 2015
Note that "w" must be a row vector whereas "s" must be a column vector if you want to use Thorsten's code.
Best wishes
Torsten.

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Torsten
Torsten am 5 Nov. 2015

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sum_total=0.0;
for i=1:(N-1)
sum_j=0.0;
for j=(i+1):N
sum_j = sum_j + w(j)*sigma(j);
end
sum_total = sum_total + w(i)*sigma(i)*sum_j;
end
sum_total = 2.0*sum_total;
Best wishes
Torsten.

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