Implicit Functions and Iterative Processes in Hydraulics
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In hydraulics you can use the Colebrook Equation to find friction factor. This is an implicit function.
How does MATLAB handle implicit functions? This method is used in an iterative approach. How would I start picking this equation apart to write a code for an implicit function?
Thank you
Antworten (2)
Andrew Newell
am 29 Dez. 2011
MATLAB handles implicit functions by changing f(x)=g(x) into f(x)-g(x)=0 and solving for x. Here is an example inspired by your link:
A = 0.1; B = 1;
fcn = @(x) 1./x+2.*log10(A + B./x);
xp = 1:.1:10; yp = fcn(xp); plot(xp,yp)
sqrtf = fzero(fcn,2);
f = sqrtf^2;
disp(['f = ',num2str(f)])
I have used an anonymous function, but you can also define functions in a variety of other ways (see Types of functions).
Sean de Wolski
am 29 Dez. 2011
0 Stimmen
Some recommended reading:
Number 32 (33 in the actual HTML)
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