Index exceeds matrix dimensions​..........​.error

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D S Parihar
D S Parihar am 22 Sep. 2015
Kommentiert: Walter Roberson am 22 Sep. 2015
when i run this code i get the index exceeds matrix dimension error
clear
a='D:\Seismic Data';
b=dir(fullfile(a));
L1=length(b);
for i=3:L1
c=dir(fullfile(a,b(i).name));
d=fullfile(a,b(i).name,c(7).name);
e=headerInfo(d);
f=e{6,6};
g=strsplit(f,':');
s1{i-2,:}=e{8,3};
s2{i-2,:}=e{5,6};
s3{i-2,:}=e{5,11};
s4{i-2,:}=g{1};
s5{i-2,:}=g{2};
end
y=[s1 s2 s3 s4 s5];
xlswrite('D:\Test MATLAB\Myprogram2.xlsx',y,'sheet1','R2')
  3 Kommentare
D S Parihar
D S Parihar am 22 Sep. 2015
in 7th line
D S Parihar
D S Parihar am 22 Sep. 2015
for i=3 it is working well but as i=4 then is could not load all the directory in c.

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Antworten (1)

Sunny Billava
Sunny Billava am 22 Sep. 2015
Are you sure you want to hard-code index of c to c(7) on line 5?
  2 Kommentare
D S Parihar
D S Parihar am 22 Sep. 2015
yes c(7) is hard-code index.
Walter Roberson
Walter Roberson am 22 Sep. 2015
How can you be positive there will always be at least 7 files there?
Also you are not taking into account that the order of files returned is not fixed, and depends on the file system (not the operating system). If you need a particular name then you should use it.

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