Hi i attached simple code,i need to store every result from for loop on each iteration,please see my code and alter it sir.

t=[1 2 3 4 5];
for i=1:4
for j=1:5
g=i+j;
l=max(g);  %Here i need to save l value in one array,likewise save l value for all iteration
end
end

[Mathieu]

Use concatenation ?

%Initialisation
l = [];
% Calculation and concatenation
for i=1:4
   for j=1:5
      new_value = ... ;
      l = [l new_value];
   end
end

Or initialise an array yourself :

   %Initialisation
    l = zeros(1, 4*5);
  % Calculation
    for i=1:4
       for j=1:5
          new_value = ... ;
          l(5*(i-1)+j) = new_value;
       end
    end

[Walter Roberson]

g is going to be a scalar. What is the point of using max() on the scalar?

[kaavya subramani]

yes sir,g is scalar.in ist iteration i=1 is added with j=1:5.so result is 2,3,4,5,6.i need to rerieve max value(i.e)6.whereas in next iteration i=2 and j=1:5,so result is 3,4,5,6,7.so i need to save max value (i.e) 7.likewise i need to save all the max value in all iteration in array

Answer 1

[Walter Roberson]

nt = length(t);
for i = 1:4
  g = zeros(nt,1);
  for j = 1:nt
    g(j) = i + t(j);
  end
  l(i) = max(g);
end

or more simply

for i = 1 : 4
  g = i + t;
  l(i) = max(g);
end