how to find repeated value in a matrix?

I have two date vectors calculated using datevec. let's say u=[10 25; 10 26; 10 27; 10 28; 10 29; 10 30; 11 0; 11 1; 11 2]; v=[10 26; 10 27; 10 28; 10 29; 11 0; 11 0; 11 2];

So I want to match same dates in u and v and save the matched dates in a different vector. I used this syntax:

find_same_dates=ismember(u,v,'rows'); row_number=find(find_same_dates==1); matched_dates=u(row_number,:); matched_dates=[10 26; 10 27; 10 28; 10 29; 11 0; 11 2];

What should I do instead if I want matched_dates to have repeated values. for example, matched_dates=[10 26; 10 27; 10 28; 10 29; 11 0; 11 0; 11 2];

'ismember' syntax doesn't match the repeated rows

Answer 1

[Azzi Abdelmalek]

That depends on how you use ismember, you have also to specify if you are looking for dates in u or in v

u=[10 25; 10 26; 10 27; 10 28; 10 29; 10 30; 11 0; 11 1; 11 2];
v=[10 26; 10 27; 10 28; 10 29; 11 0; 11 0; 11 2]
find_same_dates=ismember(v,u,'rows');
matched_dates=v(find_same_dates,:)

[Pree]

the length of u is larger than the length of v. So I want to match the dates of v with u. That is why I used this syntax: matched_dates= u(row_number,:);

row_number contains the row numbers of vector u that has same dates as in vector v.

But how should I tweak ismember syntax so it includes repeated rows? or what other functions can I use?

[Azzi Abdelmalek]

u=[10 25; 10 26; 10 27; 10 28; 10 29; 10 30; 11 0; 11 1; 11 2];
v=[10 26; 10 27; 10 28; 10 29; 11 0; 11 0; 11 2;45 45]
idu=ismember(u,v,'rows');
b=u(idu,:)
idv=ismember(v,b,'rows')
out=v(idv,:)

[Pree]

Thank you.