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i not able to find error..not getting right plot

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khushi
khushi am 17 Aug. 2015
Kommentiert: dpb am 18 Aug. 2015
clc;
clear all;
k=1;
g=0.01:.1:6;
lambda=2;
b=2;
c=1;
l=2;
for x=0.01:.1:6
T=[];
P=(0.5*lambda)/((b^(lambda*c))*gamma(c));
Q=(k^0.5)*l^(lambda*c-0.5)/((2*pi)^(0.5*(l+k)-1));
R=evalin(symengine, sprintf('meijerG([[1],[]], [[1,0.5],[]],%f)',x^2));
T=[T P*Q*R];
end
plot(g,T)

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dpb
dpb am 17 Aug. 2015
for x=0.01:.1:6
T=[];
...
T=[T P*Q*R];
end
plot(g,T)
You wipe out T every pass thru the loop so the result is simply the last P*Q*R computed. Move that outside the loop altho "growing" an array like this dynamically is not good practice; use preallocation and fill instead.
T=zeros(size(0.01:0.1:6)); % preallocate
ix=0; % array index
for x=0.01:0.1:6
...
ix=ix+1;
T(ix)=P*Q*R;
end
Or, use the loop for an integer variable and compute x dynamically as x=x+dx;
  4 Kommentare
khushi
khushi am 18 Aug. 2015
Yes
dpb
dpb am 18 Aug. 2015
In that case, you've got to allocated a square array instead of a vector and store into it...
T(ix,:)=P*Q*R;

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