How to pick a value according to its probability
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Steven
am 7 Dez. 2011
Kommentiert: Real User
am 28 Apr. 2023
Hi,
Let's say
P = [0.1 0.3 0.4 0.2]
X = [1 2 5 9]
where P(n) is the probability to select the X(n) element. I wish to make a function that select a "random" element of X according to its probability, like
f = myfun(P,X)
>> f = 2 (occurs around 30%)
thx a lot
4 Kommentare
Akzeptierte Antwort
Sean de Wolski
am 7 Dez. 2011
f = X(find(rand<cumsum(P),1,'first'))
1 Kommentar
Walter Roberson
am 7 Dez. 2011
The answers in the other thread took care in case cumsum(P) < 1 as can happen due to round-off error.
Weitere Antworten (3)
Jonathan
am 3 Sep. 2018
Bearbeitet: Jonathan
am 3 Sep. 2018
The accepted answer is not doing any sanity check, and is sensitive to rounding errors. You should use randsample instead.
To sample n points from X, with replacement, and probabilities P:
randsample( X, n, true, P )
This can also be used with a custom RandStream (see documentation). Be aware that this function does NOT check for negative values in P; check manually if needed.
4 Kommentare
Steven Lord
am 16 Apr. 2020
You can use discretize (which didn't exist when this question was asked originally) to do this. Generate uniform random numbers, bin them using bins whose widths are given by P, and for each bin return the corresponding element of X.
P = [0.1 0.3 0.4 0.2];
X = [1 2 5 9];
values = discretize(rand(1, 1e4), cumsum([0 P]), X);
histogram(values, 'Normalization', 'probability')
The probabilities shown in the histogram should agree pretty closely with the values in P.
0 Kommentare
Mendi
am 9 Jul. 2021
The fastest one (100ns-200ns):
function [idx] = get_random_choice(p)
% Random choice with probability
% Example: get_random_choice([0.2,0.7,0.1])
N=length(p); idx=1; cump=0;
r=rand;
while(idx<N)
cump=cump+p(idx);
if(cump>r),break,else,idx=idx+1;end
end
end
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