log and Exponential Equations: logb^300=30, find b)
Ältere Kommentare anzeigen
Exponential Equations: logb^300=30, find b)
1 Kommentar
the cyclist
am 31 Jul. 2015
Do you mean
log(b^300)
or
(log(b))^300
?
Antworten (2)
Azzi Abdelmalek
am 31 Jul. 2015
syms b
sol=solve(log(b^300)==30)
Star Strider
am 31 Jul. 2015
This is fairly straightforward.
log(b^300) = 300*log(b)
log(b) = 30/300
exp(log(b)) = b = exp(0.1)
Use MATLAB to get the numbers:
b = exp(30/300);
check = 300*log(b)
b =
1.1052
check =
30.0000e+000
Kategorien
Mehr zu Physics finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!