To accept two numbers from the user; Display all prime numbers between these two numbers.
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BeTrayer EK
am 28 Mai 2015
Kommentiert: BeTrayer EK
am 28 Mai 2015
To accept two numbers from the user; Display all prime numbers between these two numbers.
To accept two numbers from the user and display perfect numbers between these two numbers.
To accept two numbers from the user and display Armstrong number between these numbers.
Simple coding using DoWhile, IfElse
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Akzeptierte Antwort
B.k Sumedha
am 28 Mai 2015
Bearbeitet: Andrei Bobrov
am 28 Mai 2015
clc
num1 =input('Enter num1 value ');
num2 =input('Enter num2 value ');
n = num1 : num2;
p = isprime(n);
n(p) %displays the primes
Weitere Antworten (2)
B.k Sumedha
am 28 Mai 2015
Try this for Armstrong number:
clear, clc
% Let i take two numbers say 100 to 999
for i = 100 : 999
% We examine every digit in i
is = num2str(i);
% i1 is the left-most digit in i
i1 = str2num(is(1));
% i2 is the middle digit
i2 = str2num(is(2));
% i3 is the right-most digit in i
i3 = str2num(is(3));
% We calculate the probable AN
an = i1^3 + i2^3 + i3^3;
% We compare to the number itself
if i == an
% We display the pair of equal numbers
disp([i an])
end
end
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B.k Sumedha
am 28 Mai 2015
This is for perfect numbers where u can change the values of m and n where they are the two input numbers
n=100;
m=10;
output = zeros(1,n);
for i = m:n
test = 1:i-1;
if (sum(test(mod(i,test) == 0)) == i)
output(i) = i;
end
end
output(output == 0) = []
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