Info

Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.

can someone explain me this code please?

3 Ansichten (letzte 30 Tage)
Anonymous Learner
Anonymous Learner am 27 Mai 2015
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
clc;
clear all;
close all;
f=@(x)x.^3;
a=1;b=2;
n=1.25;
h=(b-a)/n;
p=0;
for i=a:b
p=p+1;
x(p)=i;
y(p)=i.^3;
end
l=length(x);
x
y
answer=(h/2)*((y(1)+y(l))+2*(sum(y)-y(1)-y(l)))

Antworten (1)

Roger Stafford
Roger Stafford am 27 Mai 2015
This looks like a misguided attempt to use trapezoidal approximation to find the integral of y = x^3 over an interval in x. The values assigned to 'a', 'b', and 'h' are inappropriate for such an interpretation however.
Anyhow, there is a much easier method for such an integral using calculus:
answer = (b^4-a^4)/4;
Why do numerical approximation when such an easy formula exists with the exact answer?

Diese Frage ist geschlossen.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by