I want to create a matrix that has first row as month second as date and the third as day
So far I am successful in creating three vectors and now I want to merge them in a matrix
function A=Jume2015
month = repmat('June', 30, 1);
date=[1:30];
d = {'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'};
dy = (d(mod(0:29, 7) + 1));
They should be merged in manner that I should get an output like this
>> m(11,:)
ans =
'June' [11] 'Thu'
Please help me.
If there are some errors in English please avoid them as English is a second language for me

 Akzeptierte Antwort

Jos (10584)
Jos (10584) am 26 Mai 2015

1 Stimme

A cell array is very useful when you want to combine strings and numerical values into a single matrix. Let's build one:
MonthName = 'June' ;
DayNames = {'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'};
Ndays = 30 ;
M = cell(Ndays,3) ; % create a place holder
M(:,1) = {MonthName} % fill the first two with the same string
M(:,2) = num2cell(1:Ndays) % convert numbers to a cell array
M(:,3) = DayNames(1+mod(0:Ndays-1,7)) % math trick to index into DayNames

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 26 Mai 2015

0 Stimmen

function A=Jume2015
month = repmat('June', 30, 1);
date=[1:30];
d = {'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'};
dy = (d(mod(0:29, 7) + 1));
A = [cellstr(month),num2cell(date(:)),dy(:)];

1 Kommentar

ammar ansari
ammar ansari am 26 Mai 2015
Bearbeitet: ammar ansari am 26 Mai 2015
Thanks thats a little bit close to what I was searching for but still it store dy as 1*1 cell rather then a string 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'

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