Using for loop with if condition

Respectd Team,

I am looking solution for genration of data load by text.

My problem in simple manner, We have 14 floor building with 20 rooms in each floor, I have to write a code for once the person is enter into the room 1st floor 101 and remaining values in corresponding top floors should be zer (ex :201,301....1401) and if the person enter into 2room no 415 (4 floor & no 15) than correpsonding values in 115,215,315,515....1415 should be zero.

Answer 1

[Walter Roberson]

MaxFloors = 14;
MaxRooms = 20;

BuildingData = zeros(MaxFloors, MaxRooms);

FloorRoomData = [1 1; 4 15];

for Row = 1 : height(FloorRoomData);
    FloorIndex = FloorRoomData(Row, 1);
    RoomIndex = FloorRoomData(Row, 2);
    BuildingData(:, RoomIndex) = 0;
    BuildingData(FloorIndex, RoomIndex) = 1;
end

BuildingData

BuildingData = 14×20

1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

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[G Suresh]

Thnak you for your quick reponse.

I need more clarification, if all the floors should be verified with value along with condition.

My problem as follows, I have text data need to load and print as required format. Out put is not printing as per our requirement

M=load('HST.txt')
l=32;% number of layers
z=61; % number of zones
n=l*z;
fs1=fopen('section.txt','w');
fprintf(fs1,'/prep7\n');
for i=1:z
    for j=1:l
        t(i,j)=M(i,j)
    end
end
B=t(:)'; % transpose and reshape matrix
k=1;
j=1;
ln=0;
for i=1:n
       if B(1,i)>0
          fprintf(fs1,'sect%d, shell,\n',j); 
          %% 
       
          if ln==k;
              for k=1:ln %% number of layer
                  fprintf(fs1,'secdata,0, %f, %f\n',M(i,k+32),M(i,k+64)); 
              end
             fprintf(fs1,'secdata %f, %f, %f\n',t(i,k),M(i,k+32),M(i,k+64));
          else
              for k=ln:32  %% number of layer 
                  fprintf(fs1,'secdata,0, %f, %f\n',M(i,k+32),M(i,k+64)); 
              end
   j=j+1;
    k=k+62;
          end
       end
     end
     

[Walter Roberson]

for i=1:z
    for j=1:l
        t(i,j)=M(i,j)
    end
end

That can be more easily done as

t = M(1:z, 1:l);

[Walter Roberson]

You have presented code with few useful comments. Under the circumstances, we must understand that the defined requirements of the code are identical to the current implementation of the code, that the purpose of the code is to compute exactly whatever it presently calculates. Therefore, you are incorrect that the code is not printing as per your requirement, since your requirement is defined by exactly what it prints.