Integer conversion without precision loss for literal function inputs

28 Ansichten (letzte 30 Tage)
AB
AB am 20 Nov. 2025
Kommentiert: Matt J am 19 Dez. 2025 um 15:15
The function uint64 can take a literal input that is not representable by double and convert without precision loss, like
uint64(7725400999518902274)
ans = uint64 7725400999518902274
Unfortunately, this functionality does not seem to extend to a function with an argument block and type validation.
function test(a)
arguments
a (1,1) uint64
end
disp(a)
end
test(7725400999518902274)
7725400999518902272
I would have to do
test(uint64(7725400999518902274))
7725400999518902274
Does anyone know if there is a trick to get this functionality or I am otherwise missing something?
  4 Kommentare
Dyuman Joshi
Dyuman Joshi am 20 Nov. 2025
"The function uint64 can take a literal input that is not representable by double and convert without precision loss"
That is not true, it can do that within [0, 2^64-1]
uint64(123456789012345678901)
ans = uint64 18446744073709551615
uint64(2^64-1)
ans = uint64 18446744073709551615
uint64(2^64+1)
ans = uint64 18446744073709551615
AB
AB am 20 Nov. 2025
Thanks everyone for the discussion, this might have been a bit of an unfair question without an answer beyond "no, there isn't".
To clarify, uint64 provides a special execution path that allows a literal that is not representable by a double but is representable by a uint64 to be created as a uint64 without precision loss, and I was hoping there might be a similar special handling that utilizes the arguments block.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Matt J
Matt J am 20 Nov. 2025
Bearbeitet: Matt J am 20 Nov. 2025
test 7725400999518902274
a = uint64 7725400999518902274
function test(a)
arguments
a (1,:) string
end
a=eval("uint64("+ a + ")"),
end
  8 Kommentare
Paul
Paul am 19 Dez. 2025 um 4:02
Is there any reason to prefer command syntax? Function syntax seems to work fine.
test 7725400999518902274
a = uint64 7725400999518902274
test("7725400999518902274")
a = uint64 7725400999518902274
function test(a)
arguments
a (1,:) string
end
a=eval("uint64("+ a + ")"),
end

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 21 Nov. 2025
Does anyone know if there is a trick to get this functionality
There is no way of doing that.
Any way of doing that would have to affect the inputs at parse time. However, arguement blocks do not affect parse time. Arguement blocks apply conversions to whatever input was passed in. By the time the arguement block processing is applied, the parameter has already been parsed as double precision.

Kategorien

Mehr zu Characters and Strings finden Sie in Help Center und File Exchange

Produkte


Version

R2024b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by