loop inside Index of matrix

On the following code

function [d] = matrix( n ) 
  d=zeros(2*n-1);
  for i=1:n
      d(i:end-i+1,i:end-i)=i;
  end
  end

How does the following runs?

d(i:end-i+1,i:end-i)=i;

first the rows index increase or the columns? or both at the same time?

Answer 1

[Walter Roberson]

MATLAB always goes columns first when there is a range. But it doesn't matter when you are assigning a scalar to the block, as all elements of the block are going to be given the same result.