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Matlab code for calculating characteristics equation

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Sunday
Sunday am 22 Aug. 2024 um 8:37
Kommentiert: Torsten am 23 Aug. 2024 um 22:22
I have the code below to obtain the characteristic equation of a 6by6 matrix but it giving me an error of sym
% Define a symbolic 6x6 matrix with entries as a mixture of alphabet letters and zeros
syms a b c d e f g h i j k l m n p q r s t I v w x y z
A = [-a 0 b -c d e; f -g 0 0 h 0; 0 0 -i c 0 e; 0 0 j -k 0 0; 0 0 0 l -m 0; 0 0 0 n 0 -p];
% Calculate the characteristic polynomial of the matrix A
char_eqn = charpoly(A);
disp('The characteristic equation of the matrix A is:')
disp(char_eqn)

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Shubham
Shubham am 22 Aug. 2024 um 8:42
Hi Sunday,
The error you're encountering is likely due to the fact that you haven't initialized the symbolic variables correctly or are using them incorrectly. In MATLAB, you need to ensure that all the variables used in the matrix are defined as symbolic. Here's how you can define a symbolic matrix and calculate its characteristic polynomial:
% Define symbolic variables
syms a b c d e f g h i j k l m n p
% Define the 6x6 matrix
A = [-a 0 b -c d e;
f -g 0 0 h 0;
0 0 -i c 0 e;
0 0 j -k 0 0;
0 0 0 l -m 0;
0 0 0 n 0 -p];
% Calculate the characteristic polynomial of the matrix A
char_eqn = charpoly(A);
% Display the characteristic equation
disp('The characteristic equation of the matrix A is:')
The characteristic equation of the matrix A is:
disp(char_eqn)
Key Points:
  • Ensure all variables used in the matrix are defined as symbolic using syms.
  • The charpoly function is used to compute the characteristic polynomial of the matrix.
  • The disp function is used to display the result.
This should resolve the error and correctly compute the characteristic equation of the matrix.
  3 Kommentare
Walter Roberson
Walter Roberson am 23 Aug. 2024 um 20:21
You failed to specify which variable you wanted the characteristic polynomial with respect to.
Torsten
Torsten am 23 Aug. 2024 um 22:22
I think "charpoly" simply computes the coefficients of characteristic polynomial of the matrix A, doesn't it ?

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