BTW I tried addvars() for a while as help said to do but never got that to work following all the examples the best I could
Adding a column to a UITable and then using it.
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Alessandro Livi
am 21 Jul. 2024
Kommentiert: Voss
am 22 Jul. 2024
After a few hours of trying I finally was able to add a column to a UITable
A = zeros([1 size(app.StimInputTable.Data,1)]);
app.StimInputTable.Data.Var4 = A'; % Have to make A a column vector!
for ii = 1:size(app.StimInputTable.Data,1)
app.StimInputTable.Var4(ii) = ...
app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
But now...
assigning a value to Our new column Var4 gives me
Unrecognized method, property, or field 'Var4' for class 'matlab.ui.control.Table'.
It know what app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
is so now put it in Var4! How hard can that be?
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ ____
4 5 0 0
5 4 1 0
2 3 2 0
3 2 5 0
I can do it 1 row at a time from theCommand window:
K>> app.StimInputTable.Data
ii = 1 (etc)
K>> app.StimInputTable.Data.Var4(ii) = app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii)
Although the "answer" I get is my whole
app =
MouseOdor4 with properties:
MouseOdor: [1×1 Figure]
all the properties of the whole app I won't bore you with
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ _______
4 5 0 1
5 4 1 2
2 3 2 0.66667
3 2 5 2.5
Look it worked!
Next step if you don't mind anwering is to sort the table by the Var4 column
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