Plotting sine functions using linspace command

64 Ansichten (letzte 30 Tage)
Spaceman
Spaceman am 25 Feb. 2024
Kommentiert: Spaceman am 21 Mär. 2024
Given:
Find: Create a variable y that calculates the following function for the range of t.
The variable, t, should contain 450 data points, in the interval shown below. You should be using the linspace command for this because you are provided with the number of points in the array.
Don't forget your operators! You are calculating the value of y at each individual element of t.
Once you have your t and y vectors filled with values, plot y as a function of t. Remember that, when using the plot function, there should be 2 input arguments: the horizontal coordinates come first and the vertical come second. Try adding the following code to label your plot:
xlabel('t')
ylabel('y')
title('Plotting Sine Functions')
My Solution: I got as far as to state the following:
t = linspace(-4*pi,4*pi,450);
y = 4*t*sin*(2*t);
plot(t,y)
However I was getting an error in my y...
  4 Kommentare
Spaceman
Spaceman am 26 Feb. 2024
I was having trouble obtaining this plot, due to the error I was getting with my y code line. Operators I believe refer to the element operator .* needed to properly calculate all of the points.
Spaceman
Spaceman am 26 Feb. 2024
This was what was being asked for :
t = linspace(-4.*pi,4.*pi,450);
y = 4.*t.*sin(2.*t); % Might be abusing element operators here, but doesn't hurt
plot(t,y)
xlabel('t')
ylabel('y')
title('Plotting Sine Functions')

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Hassaan
Hassaan am 25 Feb. 2024
Bearbeitet: Hassaan am 25 Feb. 2024
@Kyle Weaver I recommend 'MATLAB Learning Material' and 'References' for further understanding.
% Define the range of t with 450 data points between -4*pi and 4*pi
t = % write the linspace command here
% Calculate y for each t using the given function: y = sin(t)
y = % write the function 'y' command here
% Plotting y as a function of t
plot(t, y)
xlabel('t')
ylabel('y')
title('Plotting Sine Functions')
grid on
MATLAB Learning Material:
References
---------------------------------------------------------------------------------------------------------------------------------------------------
If you find the solution helpful and it resolves your issue, it would be greatly appreciated if you could accept the answer. Also, leaving an upvote and a comment are also wonderful ways to provide feedback.
Professional Interests
  • Technical Services and Consulting
  • Embedded Systems | Firmware Developement | Simulations
  • Electrical and Electronics Engineering
Feel free to contact me.
  5 Kommentare
Dyuman Joshi
Dyuman Joshi am 27 Feb. 2024
@Kyle, that is a part of a pre-defined message that I (and many other contributors) use. It's a like an auto-generated message.
I guess you might have just forgot to attach your code. I hope you won't forget it from now onwards.
As there are many homework questions being asked frequently on this forum without any efforts shown, expecting us to solve it for them, we have became a bit strict about this.
We are always happy to help/guide, but we won't do others hw for them.
A suggestion - You could take the free MATLAB Onramp tutorial to learn the essentials and syntax of MATLAB.
Spaceman
Spaceman am 21 Mär. 2024
Thank you.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Sam Chak
Sam Chak am 25 Feb. 2024
It says to plot y as a function of t. You can follow this example to make the plot.
You can learn more about linspace() and plot() in the documentation.
y = @(t) sin(pi*t).*(cos(pi*t)); % create y as a function of t
t = linspace(-pi/2, pi/2, 900); % use linspace to create 900 points over the range -π/2 < t < π/2
plot(t, y(t)), grid on % make the plot
  2 Kommentare
Spaceman
Spaceman am 26 Feb. 2024
Genius. What does the @ symbol accomplish here?
Sam Chak
Sam Chak am 26 Feb. 2024
@Kyle Weaver, It's a way of creating an anonymous function. Check out this article:

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Get Started with MATLAB finden Sie in Help Center und File Exchange

Tags

Produkte


Version

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by