matrix calculation reshaping and diferences between datum
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Vasco
am 2 Jan. 2024
Kommentiert: Cris LaPierre
am 4 Jan. 2024
i dont know how to transform the Z dimension into a 2x2 matriz at least i dont understand how to make it run
7 Kommentare
Voss
am 2 Jan. 2024
Where would the country border come from?
I don't know what's going on either; you'll need to step through your code and check that each variable seems reasonable (correct size, reasonable values) as it runs, and find where it goes wrong and fix it.
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Cris LaPierre
am 2 Jan. 2024
Also, you can simplify your code a little by accessing the data in your tables more directly. See here: https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-table.html
Here's the relevant pieces of code. Note that I am not claiming to solve your assignment for you. Just get you started.
%Inserção dos dados e criação de variáveis
file_in=readtable("RGN_ETRS89_geod.txt");
lat_dec = dms2degrees(file_in{:,["Latd","Latm","Lats"]});
lon_dec = -1*dms2degrees(file_in{:,["Lond","Lonm","Lons"]});
alt_orto = file_in.h;
alt_elips = file_in.H;
% scatterm(lat_dec,lon_dec)
k = boundary(lat_dec,lon_dec);
geoshow(lat_dec(k),lon_dec(k))
%Elipsoide de referência para ETRS89: GRS80
a=6378137;
f=1/298.257222101;
b=a*(1-f);
e=(sqrt(a^2-b^2))/a;
N=a./sqrt(1-e^2.*(sind(lat_dec)).^2);
%Cálculo de X, Y e Z
X=(N+alt_elips).*cosd(lat_dec).*cosd(lon_dec);
Y=(N+alt_elips).*cosd(lat_dec).*sind(lon_dec);
Z=(N.*(1-e^2)+alt_elips).*sind(lat_dec);
%Exercício 2
%2.1
Tx=230.994;
Ty=-102.591;
Tz=-25.199;
omegax=deg2rad(-0.633/3600);
omegay=deg2rad(0.239/3600);
omegaz=deg2rad(-0.900/3600);
D=-1.950*10^-6;
matriz=[1 -omegaz omegay; omegaz 1 -omegax; -omegay omegax 1];
for i=1:1668
D73=[Tx;Ty;Tz]+(D+1)*matriz*[X(i);Y(i);Z(i)];
XD73(i,1)=D73(1);
YD73(i,1)=D73(2);
ZD73(i,1)=D73(3);
end
%2.2
Tx=283.088;
Ty=70.693;
Tz=-117.445;
omegax=deg2rad(1.157/3600);
omegay=deg2rad(-0.059/3600);
omegaz=deg2rad(0.652/3600);
D=4.058*10^-6;
matriz=[1 -omegaz omegay; omegaz 1 -omegax; -omegay omegax 1];
for i=1:1668
DLx=[Tx;Ty;Tz]+(D+1)*matriz*[X(i);Y(i);Z(i)];
XDLx(i,1)=DLx(1);
YDLx(i,1)=DLx(2);
ZDLx(i,1)=DLx(3);
end
%Elipsóide de referência para o Datum 73 e Datum Lisboa - Hayford
a_D73= 6378388;
f_D73=1/297;
b_D73=a_D73*(1-f_D73);
e_D73=(sqrt(a_D73^2-b_D73^2))/a_D73;
%Datum Lisboa
%Determinação da latitude
%Estimativa inicial
p=sqrt(XDLx.^2+YDLx.^2);
lat_0=atand(ZDLx./p);
N_0=a_D73./sqrt(1-e_D73^2.*(sind(lat_0)).^2);
%Primeira iteração
lat_1=atand((ZDLx+e_D73^2.*N_0.*sind(lat_0))./p);
N_1=a_D73./sqrt(1-e_D73^2.*(sind(lat_1)).^2);
%Segunda iteração
lat_2=atand((ZDLx+e_D73^2.*N_1.*sind(lat_1))./p);
N_2=a_D73./sqrt(1-e_D73^2.*(sind(lat_2)).^2);
%Terceira iteração
lat_3_DLx=atand((ZDLx+e_D73^2.*N_2.*sind(lat_2))./p);
%DLX figura e D73 figura
delta_lat_Dlx = lat_dec - lat_3_DLx;
% Create a function for predicting delta_lat_Dlx based on lat & lon data
F = scatteredInterpolant(lon_dec,lat_dec,delta_lat_Dlx);
% Create a 2d grid of Lat and Lon values
[LON,LAT] = meshgrid(-10:0.1:-6,36:0.05:43);
% Predict gridded values for delta_lat_Dlx
Z = F(LON,LAT);
% set values outside portugal to nan (so they do not appear in contour plot
in = inpolygon(LAT,LON,lat_dec(k),lon_dec(k));
Z(~in) = nan;
% Create a contour plot
hold on
contourm(LAT,LON,Z,10,'r','ShowText','on')
hold off
6 Kommentare
Cris LaPierre
am 4 Jan. 2024
I wouldn't expect subplot to fix the issue. Please try what I suggested.
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