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how to solve log log equation??

1 Ansicht (letzte 30 Tage)
mahmoud abougharara
mahmoud abougharara am 23 Dez. 2023
Bearbeitet: Torsten am 23 Dez. 2023
clc ,clear
syms m
m1=7;
m2=9.41;
t1=273+30;
t2=273+50;
t=40+273
t = 313
b=(log10(log10(m1))-log10(log10(m2)))/((log10(t1)-(log10(t2))));
a=log10(log10(m1))-b*log10(t1);
a
a = -5.5678
b
b = 2.2143
log10(log10(m))=a-b*log10(t);
Error using indexing
Invalid indexing or function definition. Indexing must follow MATLAB indexing. Function arguments must be symbolic variables, and function body must be sym expression.
solve(m)

Antworten (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 23 Dez. 2023
Here is the corrected code (note how the EQN is set up for the given equation):
clc, clearvars
syms m
m1=7;
m2=9.41;
t1=273+30;
t2=273+50;
t=40+273;
b=(log10(log10(m1))-log10(log10(m2)))/((log10(t1)-(log10(t2))));
a=log10(log10(m1))-b*log10(t1);
fprintf('a = %f; b = %f \n', [a, b])
a = -5.567761; b = 2.214304
EQN =log10(log10(m))==a-b*log10(t);
SOL = solve(EQN);
fprintf('Solution: m = %1.16f with solve() \n', double(SOL));
Solution: m = 1.0000000000185594 with solve()
  1 Kommentar
Torsten
Torsten am 23 Dez. 2023
Bearbeitet: Torsten am 23 Dez. 2023
Or
m = 10^(10^(a-b*log10(t)))

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