How to solve interdependent differtional equations
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Hi
I have a system of three differetional equations
I defined my function as follow
function dydx = StratNoObs(x, y)
D=1; %depth [m]
rho_bs=2000;%[kg/m3]
rho_ts=1000;%[kg/m3]
drho_dy=rho_bs-rho_ts/D;
rho_t = rho_ts/(rho_bs*drho_dy); %
rho_b = rho_bs/(rho_bs*drho_dy); % [kg/m3]
U=1;
Ri = (9.81*D^2*drho_dy)/(U^2*rho_bs);
Re = 100;
diffusifty = 0.000025; %[m2/s]
mu = 0.001002; % [kg/(m.s)]
Sc= (mu/(rho_bs*diffusifty)); %the ratio of the coefficient of diffusion to the kinematic viscosity
d_rho=rho_t/rho_b;
b = y(1);
f = y(2);
e = y(3);
dbdx = (280.*e+(1400/3).*f)./(Ri*Re);
fA = -(2.*f)./(Re);
fB = -Ri*(-4/735).*dbdx;
fC = (1/Re).*(-(1/3).*e-(2/9).*f);
fD = -((13/11340).*e+(31/17010).*f+(1/90));
fF = -dbdx*((-21*.e-41*.f-1404)./(882.*(rho_b-rho_t+(1/42).*b)));
fG = -(1080.*b)./(Re.*Sc.*(42.*rho_b-42.*rho_t+(1/42).*b));
fI = -(1470.*rho_b-1470.*rho_t+41.*b)/(882.*rho_b-882.*rho_t+21.*b);
fJ = ((31/17010).*e+(76/25515).*f+(1/54));
dfdx = (fA+fB+fC+fD.*(fF+fG)./(-fD.*fI+fJ);
dedx = fI.*dfdx+fF+fG;
dydx = [dbdx; dfdx; dedx];
end
I am not getting the expected answer so is I am questioning if it is ok to call the dbdx and dfdx in the defintion dedx?
Thank you
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Antworten (1)
Sulaymon Eshkabilov
am 9 Dez. 2023
Here is the corrected code. There were a few syntx errs and missing paranthesis.
x= linspace(0, pi);
y = [0 1 -1];
SOL=StratNoObs(x, y)
function dydx = StratNoObs(x, y)
D=1; %depth [m]
rho_bs=2000;%[kg/m3]
rho_ts=1000;%[kg/m3]
drho_dy=rho_bs-rho_ts/D;
rho_t = rho_ts/(rho_bs*drho_dy); %
rho_b = rho_bs/(rho_bs*drho_dy); % [kg/m3]
U=1;
Ri = (9.81*D^2*drho_dy)/(U^2*rho_bs);
Re = 100;
diffusifty = 0.000025; %[m2/s]
mu = 0.001002; % [kg/(m.s)]
Sc= (mu/(rho_bs*diffusifty)); %the ratio of the coefficient of diffusion to the kinematic viscosity
d_rho=rho_t/rho_b;
b = y(1);
f = y(2);
e = y(3);
dbdx = (280.*e+(1400/3).*f)./(Ri*Re);
fA = -(2.*f)./(Re);
fB = -Ri*(-4/735).*dbdx;
fC = (1/Re).*(-(1/3).*e-(2/9).*f);
fD = -((13/11340).*e+(31/17010).*f+(1/90));
fF = -dbdx*((-21.*e-41.*f-1404)./(882.*(rho_b-rho_t+(1/42).*b)));
fG = -(1080.*b)./(Re.*Sc.*(42.*rho_b-42.*rho_t+(1/42).*b));
fI = -(1470.*rho_b-1470.*rho_t+41.*b)/(882.*rho_b-882.*rho_t+21.*b);
fJ = ((31/17010).*e+(76/25515).*f+(1/54));
dfdx = (fA+fB+fC+fD.*(fF+fG))./(-fD.*fI+fJ);
dedx = fI.*dfdx+fF+fG;
dydx = [dbdx; dfdx; dedx];
end
2 Kommentare
Sulaymon Eshkabilov
am 9 Dez. 2023
Just looking at only math operations and manipulated variables here, all steps are legit. But it is said without seeing your original diff equations.
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