Conversion to cell from double is not possible.

I am trying to solve delay logistic equation with multiple delay terms but for finding delayed states i am getting error and my error is

"Conversion to cell from double is not possible."

g = @(t, y, Z, par) par(1) * y * (1 - sum(par(2:end) .* Z));
tau = [1, 1.5,2,2.5,3]; % Array of different delays
par = [1.5, 0.1,0.2,0.3,0.4,0.5];

this is my equation

and I am getting error here in this part

%% Calculate delayed states for multiple delays
x_d = cell(length(tau), 1);
for k = 1:length(tau)
    x_d(k) = deval(sol, t_t - tau(k));
end

Answer 1

[Dyuman Joshi]

You need to use curly brackets, {}

%% Calculate delayed states for multiple delays
x_d = cell(length(tau), 1);
for k = 1:length(tau)
    %  v v
    x_d{k} = deval(sol, t_t - tau(k));
end

[Muhammad]

Thank you its working

Now i am getting error in this next part and the error is "Operator '.*' is not supported for operands of type 'cell'."

x_dn = cell(size(x_d));
for k = 1:length(x_d)
    x_dn(k) = x_d(k) + eps * randn(size(x_d(k))) .* x_d(k);
end

[Dyuman Joshi]

Again, use curly brackets for cell arrays.

Read more here - Access data in a cell array

x_dn = cell(size(x_d));
for k = 1:length(x_d)
    %   v v      v v                       v v         v v
    x_dn{k} = x_d{k} + eps * randn(size(x_d{k})) .* x_d{k};
end

Also, you can combine the for loops for x_d and x_dn.

[Muhammad]

Thank you so much for help

[Matt J]

@Muhammad Please Accept-click the answer to indicate that it worked.

[Dyuman Joshi]

Thanks @Matt J.